4y-4+2(3y+5)=-2(y+1)

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Solution for 4y-4+2(3y+5)=-2(y+1) equation: 



4y-4+2(3y+5)=-2(y+1)

We move all terms to the left:

4y-4+2(3y+5)-(-2(y+1))=0

We multiply parentheses

4y+6y-(-2(y+1))+10-4=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

10y-(-2y-2)+6=0

We get rid of parentheses

10y+2y+2+6=0

We add all the numbers together, and all the variables

12y+8=0

We move all terms containing y to the left, all other terms to the right

12y=-8

y=-8/12

y=-2/3

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