4y-4+2(4y+1)=4(y+4)

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Solution for 4y-4+2(4y+1)=4(y+4) equation: 



4y-4+2(4y+1)=4(y+4)

We move all terms to the left:

4y-4+2(4y+1)-(4(y+4))=0

We multiply parentheses

4y+8y-(4(y+4))+2-4=0



We calculate terms in parentheses: -(4(y+4)), so:

4(y+4)

We multiply parentheses

4y+16

Back to the equation:

-(4y+16)



We add all the numbers together, and all the variables

12y-(4y+16)-2=0

We get rid of parentheses

12y-4y-16-2=0

We add all the numbers together, and all the variables

8y-18=0

We move all terms containing y to the left, all other terms to the right

8y=18

y=18/8

y=2+1/4

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