4y-5(y-2)=3(3y+4)+2

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Solution for 4y-5(y-2)=3(3y+4)+2 equation: 



4y-5(y-2)=3(3y+4)+2

We move all terms to the left:

4y-5(y-2)-(3(3y+4)+2)=0

We multiply parentheses

4y-5y-(3(3y+4)+2)+10=0



We calculate terms in parentheses: -(3(3y+4)+2), so:

3(3y+4)+2

We multiply parentheses

9y+12+2

We add all the numbers together, and all the variables

9y+14

Back to the equation:

-(9y+14)



We add all the numbers together, and all the variables

-1y-(9y+14)+10=0

We get rid of parentheses

-1y-9y-14+10=0

We add all the numbers together, and all the variables

-10y-4=0

We move all terms containing y to the left, all other terms to the right

-10y=4

y=4/-10

y=-2/5

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