4y-5+2y=y+3-2y

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Solution for 4y-5+2y=y+3-2y equation: 



4y-5+2y=y+3-2y

We move all terms to the left:

4y-5+2y-(y+3-2y)=0

We add all the numbers together, and all the variables

4y+2y-(-1y+3)-5=0

We add all the numbers together, and all the variables

6y-(-1y+3)-5=0

We get rid of parentheses

6y+1y-3-5=0

We add all the numbers together, and all the variables

7y-8=0

We move all terms containing y to the left, all other terms to the right

7y=8

y=8/7

y=1+1/7

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