4y-5+y+32=7y+30-5y

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Solution for 4y-5+y+32=7y+30-5y equation: 



4y-5+y+32=7y+30-5y

We move all terms to the left:

4y-5+y+32-(7y+30-5y)=0

We add all the numbers together, and all the variables

4y+y-(2y+30)-5+32=0

We add all the numbers together, and all the variables

5y-(2y+30)+27=0

We get rid of parentheses

5y-2y-30+27=0

We add all the numbers together, and all the variables

3y-3=0

We move all terms containing y to the left, all other terms to the right

3y=3

y=3/3

y=1

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