4y-5=2(5-y)

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Solution for 4y-5=2(5-y) equation: 



4y-5=2(5-y)

We move all terms to the left:

4y-5-(2(5-y))=0

We add all the numbers together, and all the variables

4y-(2(-1y+5))-5=0



We calculate terms in parentheses: -(2(-1y+5)), so:

2(-1y+5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

4y+2y-10-5=0

We add all the numbers together, and all the variables

6y-15=0

We move all terms containing y to the left, all other terms to the right

6y=15

y=15/6

y=2+1/2

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