4y-6(y+2)=14+2y

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Solution for 4y-6(y+2)=14+2y equation: 



4y-6(y+2)=14+2y

We move all terms to the left:

4y-6(y+2)-(14+2y)=0

We add all the numbers together, and all the variables

4y-6(y+2)-(2y+14)=0

We multiply parentheses

4y-6y-(2y+14)-12=0

We get rid of parentheses

4y-6y-2y-14-12=0

We add all the numbers together, and all the variables

-4y-26=0

We move all terms containing y to the left, all other terms to the right

-4y=26

y=26/-4

y=-6+1/2

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