4y-7+2=-3(y-1)-1

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Solution for 4y-7+2=-3(y-1)-1 equation: 



4y-7+2=-3(y-1)-1

We move all terms to the left:

4y-7+2-(-3(y-1)-1)=0

We add all the numbers together, and all the variables

4y-(-3(y-1)-1)-5=0



We calculate terms in parentheses: -(-3(y-1)-1), so:

-3(y-1)-1

We multiply parentheses

-3y+3-1

We add all the numbers together, and all the variables

-3y+2

Back to the equation:

-(-3y+2)



We get rid of parentheses

4y+3y-2-5=0

We add all the numbers together, and all the variables

7y-7=0

We move all terms containing y to the left, all other terms to the right

7y=7

y=7/7

y=1

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