4y-7+2y=3(y-1)1

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Solution for 4y-7+2y=3(y-1)1 equation: 



4y-7+2y=3(y-1)1

We move all terms to the left:

4y-7+2y-(3(y-1)1)=0

We add all the numbers together, and all the variables

6y-(3(y-1)1)-7=0



We calculate terms in parentheses: -(3(y-1)1), so:

3(y-1)1

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

6y-3y+3-7=0

We add all the numbers together, and all the variables

3y-4=0

We move all terms containing y to the left, all other terms to the right

3y=4

y=4/3

y=1+1/3

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