4y-8+2(2y+2)=-4(y+3)

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Solution for 4y-8+2(2y+2)=-4(y+3) equation:



4y-8+2(2y+2)=-4(y+3)
We move all terms to the left:
4y-8+2(2y+2)-(-4(y+3))=0
We multiply parentheses
4y+4y-(-4(y+3))+4-8=0
We calculate terms in parentheses: -(-4(y+3)), so:
-4(y+3)
We multiply parentheses
-4y-12
Back to the equation:
-(-4y-12)
We add all the numbers together, and all the variables
8y-(-4y-12)-4=0
We get rid of parentheses
8y+4y+12-4=0
We add all the numbers together, and all the variables
12y+8=0
We move all terms containing y to the left, all other terms to the right
12y=-8
y=-8/12
y=-2/3

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