4y-8+2(2y+2)=-4(y+3)

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Solution for 4y-8+2(2y+2)=-4(y+3) equation: 



4y-8+2(2y+2)=-4(y+3)

We move all terms to the left:

4y-8+2(2y+2)-(-4(y+3))=0

We multiply parentheses

4y+4y-(-4(y+3))+4-8=0



We calculate terms in parentheses: -(-4(y+3)), so:

-4(y+3)

We multiply parentheses

-4y-12

Back to the equation:

-(-4y-12)



We add all the numbers together, and all the variables

8y-(-4y-12)-4=0

We get rid of parentheses

8y+4y+12-4=0

We add all the numbers together, and all the variables

12y+8=0

We move all terms containing y to the left, all other terms to the right

12y=-8

y=-8/12

y=-2/3

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