4y-8+2(6y+4)=-2(y+6)

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Solution for 4y-8+2(6y+4)=-2(y+6) equation: 



4y-8+2(6y+4)=-2(y+6)

We move all terms to the left:

4y-8+2(6y+4)-(-2(y+6))=0

We multiply parentheses

4y+12y-(-2(y+6))+8-8=0



We calculate terms in parentheses: -(-2(y+6)), so:

-2(y+6)

We multiply parentheses

-2y-12

Back to the equation:

-(-2y-12)



We add all the numbers together, and all the variables

16y-(-2y-12)=0

We get rid of parentheses

16y+2y+12=0

We add all the numbers together, and all the variables

18y+12=0

We move all terms containing y to the left, all other terms to the right

18y=-12

y=-12/18

y=-2/3

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