4y-8+20y=8(3y-1)

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Solution for 4y-8+20y=8(3y-1) equation: 



4y-8+20y=8(3y-1)

We move all terms to the left:

4y-8+20y-(8(3y-1))=0

We add all the numbers together, and all the variables

24y-(8(3y-1))-8=0



We calculate terms in parentheses: -(8(3y-1)), so:

8(3y-1)

We multiply parentheses

24y-8

Back to the equation:

-(24y-8)



We get rid of parentheses

24y-24y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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