4y-8/2y-4=2

Solution for 4y-8/2y-4=2 equation:

4y-8/2y-4=2

We move all terms to the left:

4y-8/2y-4-(2)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R


We add all the numbers together, and all the variables

4y-8/2y-6=0

We multiply all the terms by the denominator


4y*2y-6*2y-8=0

Wy multiply elements

8y^2-12y-8=0

a = 8; b = -12; c = -8;
Δ = b2-4ac
Δ = -122-4·8·(-8)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-20}{2*8}=\frac{-8}{16}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+20}{2*8}=\frac{32}{16}
=2
$