4y/5y-3/2y=

Solution for 4y/5y-3/2y= equation:

4y/5y-3/2y=

We move all terms to the left:

4y/5y-3/2y-()=0


Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R


We add all the numbers together, and all the variables

4y/5y-3/2y=0

We calculate fractions


8y^2/10y^2+(-15y)/10y^2=0

We multiply all the terms by the denominator


8y^2+(-15y)=0

We get rid of parentheses

8y^2-15y=0

a = 8; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·8·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*8}=\frac{0}{16}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*8}=\frac{30}{16}
=1+7/8
$