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4y^2+43y+30=0
a = 4; b = 43; c = +30;
Δ = b2-4ac
Δ = 432-4·4·30
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-37}{2*4}=\frac{-80}{8} =-10 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+37}{2*4}=\frac{-6}{8} =-3/4 $
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