4y2+5y-12=0

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Solution for 4y2+5y-12=0 equation: 



4y^2+5y-12=0

a = 4; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·4·(-12)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{217}}{2*4}=\frac{-5-\sqrt{217}}{8}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{217}}{2*4}=\frac{-5+\sqrt{217}}{8}
$

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