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4y^2+6y+2=0
a = 4; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·4·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*4}=\frac{-8}{8} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*4}=\frac{-4}{8} =-1/2 $
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