4y2+8y=68

Solution for 4y2+8y=68 equation:

4y^2+8y=68

We move all terms to the left:

4y^2+8y-(68)=0

a = 4; b = 8; c = -68;
Δ = b2-4ac
Δ = 82-4·4·(-68)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24\sqrt{2}}{2*4}=\frac{-8-24\sqrt{2}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24\sqrt{2}}{2*4}=\frac{-8+24\sqrt{2}}{8}
$