If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4y^2-40y=100
We move all terms to the left:
4y^2-40y-(100)=0
a = 4; b = -40; c = -100;
Δ = b2-4ac
Δ = -402-4·4·(-100)
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40\sqrt{2}}{2*4}=\frac{40-40\sqrt{2}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40\sqrt{2}}{2*4}=\frac{40+40\sqrt{2}}{8} $
| 10=(700)(80)/n | | x+0.08x=198 | | 123=3+20x | | 17x+1+5x+2+7x+3=180 | | (123)5=(38)x | | -8=x=10-2 | | -7e=-49 | | x+7(x-8)+19=-16 | | 7(1-5b)=252 | | -15=a/9 | | m+(-4)=-12 | | 3+10x=-107 | | x/6+4=29 | | 20x/15=4/x | | 14+2.25x=45 | | 6x+1=2x+22 | | 4x/8-4/8=2x/7+4x/7 | | 3+8p-5=14 | | -11=r/15 | | 8y-18=6y+3 | | -2x5x-9=3(x-4)-5 | | t+15+t+45+t-8=180 | | -15x-18=-78 | | -2t+4=8t-3 | | 1/4z+2/3=1/2z-3/4 | | t/6+11=82 | | 1/2(x-32)=23+7x | | x/3=4=-5 | | 14+2.25x=6 | | 10x-15=-45+40 | | 1+3v-5=11 | | 3(2x+3)=x-13 |