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4y^2-y-33=0
We add all the numbers together, and all the variables
4y^2-1y-33=0
a = 4; b = -1; c = -33;
Δ = b2-4ac
Δ = -12-4·4·(-33)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-23}{2*4}=\frac{-22}{8} =-2+3/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+23}{2*4}=\frac{24}{8} =3 $
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