4y2=-12y-9

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Solution for 4y2=-12y-9 equation: 



4y^2=-12y-9

We move all terms to the left:

4y^2-(-12y-9)=0

We get rid of parentheses

4y^2+12y+9=0

a = 4; b = 12; c = +9;
Δ = b2-4ac
Δ = 122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-12}{8}=-1+1/2$

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