4y2=256

Solution for 4y2=256 equation:

4y^2=256

We move all terms to the left:

4y^2-(256)=0

a = 4; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·4·(-256)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*4}=\frac{-64}{8}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*4}=\frac{64}{8}
=8
$