4y=(2y-1)(2y+1)

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Solution for 4y=(2y-1)(2y+1) equation: 



4y=(2y-1)(2y+1)

We move all terms to the left:

4y-((2y-1)(2y+1))=0

We use the square of the difference formula

4y^2+4y+1=0

a = 4; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-4}{8}=-1/2$

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