4y=(3-3y)+11

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Solution for 4y=(3-3y)+11 equation: 



4y=(3-3y)+11

We move all terms to the left:

4y-((3-3y)+11)=0

We add all the numbers together, and all the variables

4y-((-3y+3)+11)=0



We calculate terms in parentheses: -((-3y+3)+11), so:

(-3y+3)+11

We get rid of parentheses

-3y+3+11

We add all the numbers together, and all the variables

-3y+14

Back to the equation:

-(-3y+14)



We get rid of parentheses

4y+3y-14=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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