4y=(y+2)+1

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Solution for 4y=(y+2)+1 equation: 



4y=(y+2)+1

We move all terms to the left:

4y-((y+2)+1)=0



We calculate terms in parentheses: -((y+2)+1), so:

(y+2)+1

We get rid of parentheses

y+2+1

We add all the numbers together, and all the variables

y+3

Back to the equation:

-(y+3)



We get rid of parentheses

4y-y-3=0

We add all the numbers together, and all the variables

3y-3=0

We move all terms containing y to the left, all other terms to the right

3y=3

y=3/3

y=1

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