4y=2(y-2)-2

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Solution for 4y=2(y-2)-2 equation: 



4y=2(y-2)-2

We move all terms to the left:

4y-(2(y-2)-2)=0



We calculate terms in parentheses: -(2(y-2)-2), so:

2(y-2)-2

We multiply parentheses

2y-4-2

We add all the numbers together, and all the variables

2y-6

Back to the equation:

-(2y-6)



We get rid of parentheses

4y-2y+6=0

We add all the numbers together, and all the variables

2y+6=0

We move all terms containing y to the left, all other terms to the right

2y=-6

y=-6/2

y=-3

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