4y=2(y-5))-2

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Solution for 4y=2(y-5))-2 equation: 



4y=2(y-5))-2

We move all terms to the left:

4y-(2(y-5))-2)=0

We add all the numbers together, and all the variables

4y-(2(y-5))=0



We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

4y-2y+10=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5

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