4y=5y-3(y-2)

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Solution for 4y=5y-3(y-2) equation: 



4y=5y-3(y-2)

We move all terms to the left:

4y-(5y-3(y-2))=0



We calculate terms in parentheses: -(5y-3(y-2)), so:

5y-3(y-2)

We multiply parentheses

5y-3y+6

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

4y-2y-6=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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