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4y=64y^2
We move all terms to the left:
4y-(64y^2)=0
determiningTheFunctionDomain -64y^2+4y=0
a = -64; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-64)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-64}=\frac{-8}{-128} =1/16 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-64}=\frac{0}{-128} =0 $
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