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4z*4z+14z=0
We add all the numbers together, and all the variables
14z+4z*4z=0
Wy multiply elements
16z^2+14z=0
a = 16; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·16·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*16}=\frac{-28}{32} =-7/8 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*16}=\frac{0}{32} =0 $
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