4z+11=3(2z-5)

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Solution for 4z+11=3(2z-5) equation: 



4z+11=3(2z-5)

We move all terms to the left:

4z+11-(3(2z-5))=0



We calculate terms in parentheses: -(3(2z-5)), so:

3(2z-5)

We multiply parentheses

6z-15

Back to the equation:

-(6z-15)



We get rid of parentheses

4z-6z+15+11=0

We add all the numbers together, and all the variables

-2z+26=0

We move all terms containing z to the left, all other terms to the right

-2z=-26

z=-26/-2

z=+13

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