4z+12(z-3)=28

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Solution for 4z+12(z-3)=28 equation:


Simplifying
4z + 12(z + -3) = 28

Reorder the terms:
4z + 12(-3 + z) = 28
4z + (-3 * 12 + z * 12) = 28
4z + (-36 + 12z) = 28

Reorder the terms:
-36 + 4z + 12z = 28

Combine like terms: 4z + 12z = 16z
-36 + 16z = 28

Solving
-36 + 16z = 28

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '36' to each side of the equation.
-36 + 36 + 16z = 28 + 36

Combine like terms: -36 + 36 = 0
0 + 16z = 28 + 36
16z = 28 + 36

Combine like terms: 28 + 36 = 64
16z = 64

Divide each side by '16'.
z = 4

Simplifying
z = 4

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