4z+12=-3z+12

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Solution for 4z+12=-3z+12 equation: 



4z+12=-3z+12

We move all terms to the left:

4z+12-(-3z+12)=0

We get rid of parentheses

4z+3z-12+12=0

We add all the numbers together, and all the variables

7z=0

z=0/7

z=0

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