4z+12=20

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Solution for 4z+12=20 equation: 



4z+12=20

We move all terms to the left:

4z+12-(20)=0

We add all the numbers together, and all the variables

4z-8=0

We move all terms containing z to the left, all other terms to the right

4z=8

z=8/4

z=2

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