4z+12=3z+7

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Solution for 4z+12=3z+7 equation: 



4z+12=3z+7

We move all terms to the left:

4z+12-(3z+7)=0

We get rid of parentheses

4z-3z-7+12=0

We add all the numbers together, and all the variables

z+5=0

We move all terms containing z to the left, all other terms to the right

z=-5

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