4z+12=7z-+(9)

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Solution for 4z+12=7z-+(9) equation: 



4z+12=7z-+(9)

We move all terms to the left:

4z+12-(7z-+(9))=0

We add all the numbers together, and all the variables

4z-(+7z)+12=0

We get rid of parentheses

4z-7z+12=0

We add all the numbers together, and all the variables

-3z+12=0

We move all terms containing z to the left, all other terms to the right

-3z=-12

z=-12/-3

z=+4

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