4z+12=7z-8

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Solution for 4z+12=7z-8 equation: 



4z+12=7z-8

We move all terms to the left:

4z+12-(7z-8)=0

We get rid of parentheses

4z-7z+8+12=0

We add all the numbers together, and all the variables

-3z+20=0

We move all terms containing z to the left, all other terms to the right

-3z=-20

z=-20/-3

z=6+2/3

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