4z+1=5(2z-1)

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Solution for 4z+1=5(2z-1) equation: 



4z+1=5(2z-1)

We move all terms to the left:

4z+1-(5(2z-1))=0



We calculate terms in parentheses: -(5(2z-1)), so:

5(2z-1)

We multiply parentheses

10z-5

Back to the equation:

-(10z-5)



We get rid of parentheses

4z-10z+5+1=0

We add all the numbers together, and all the variables

-6z+6=0

We move all terms containing z to the left, all other terms to the right

-6z=-6

z=-6/-6

z=1

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