4z+28=120

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Solution for 4z+28=120 equation: 



4z+28=120

We move all terms to the left:

4z+28-(120)=0

We add all the numbers together, and all the variables

4z-92=0

We move all terms containing z to the left, all other terms to the right

4z=92

z=92/4

z=23

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