4z+2=2(z-2)

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Solution for 4z+2=2(z-2) equation:



4z+2=2(z-2)
We move all terms to the left:
4z+2-(2(z-2))=0
We calculate terms in parentheses: -(2(z-2)), so:
2(z-2)
We multiply parentheses
2z-4
Back to the equation:
-(2z-4)
We get rid of parentheses
4z-2z+4+2=0
We add all the numbers together, and all the variables
2z+6=0
We move all terms containing z to the left, all other terms to the right
2z=-6
z=-6/2
z=-3

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