4z+2z-12=3(z+9)

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Solution for 4z+2z-12=3(z+9) equation: 



4z+2z-12=3(z+9)

We move all terms to the left:

4z+2z-12-(3(z+9))=0

We add all the numbers together, and all the variables

6z-(3(z+9))-12=0



We calculate terms in parentheses: -(3(z+9)), so:

3(z+9)

We multiply parentheses

3z+27

Back to the equation:

-(3z+27)



We get rid of parentheses

6z-3z-27-12=0

We add all the numbers together, and all the variables

3z-39=0

We move all terms containing z to the left, all other terms to the right

3z=39

z=39/3

z=13

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