4z+3(4-2)=-(z-4)+4

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Solution for 4z+3(4-2)=-(z-4)+4 equation: 



4z+3(4-2)=-(z-4)+4

We move all terms to the left:

4z+3(4-2)-(-(z-4)+4)=0

We add all the numbers together, and all the variables

4z-(-(z-4)+4)+32=0



We calculate terms in parentheses: -(-(z-4)+4), so:

-(z-4)+4

We get rid of parentheses

-z+4+4

We add all the numbers together, and all the variables

-1z+8

Back to the equation:

-(-1z+8)



We get rid of parentheses

4z+1z-8+32=0

We add all the numbers together, and all the variables

5z+24=0

We move all terms containing z to the left, all other terms to the right

5z=-24

z=-24/5

z=-4+4/5

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