4z+3(4-z)=-(z-4)+4

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Solution for 4z+3(4-z)=-(z-4)+4 equation:


Simplifying
4z + 3(4 + -1z) = -1(z + -4) + 4
4z + (4 * 3 + -1z * 3) = -1(z + -4) + 4
4z + (12 + -3z) = -1(z + -4) + 4

Reorder the terms:
12 + 4z + -3z = -1(z + -4) + 4

Combine like terms: 4z + -3z = 1z
12 + 1z = -1(z + -4) + 4

Reorder the terms:
12 + 1z = -1(-4 + z) + 4
12 + 1z = (-4 * -1 + z * -1) + 4
12 + 1z = (4 + -1z) + 4

Reorder the terms:
12 + 1z = 4 + 4 + -1z

Combine like terms: 4 + 4 = 8
12 + 1z = 8 + -1z

Solving
12 + 1z = 8 + -1z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add 'z' to each side of the equation.
12 + 1z + z = 8 + -1z + z

Combine like terms: 1z + z = 2z
12 + 2z = 8 + -1z + z

Combine like terms: -1z + z = 0
12 + 2z = 8 + 0
12 + 2z = 8

Add '-12' to each side of the equation.
12 + -12 + 2z = 8 + -12

Combine like terms: 12 + -12 = 0
0 + 2z = 8 + -12
2z = 8 + -12

Combine like terms: 8 + -12 = -4
2z = -4

Divide each side by '2'.
z = -2

Simplifying
z = -2

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