4z+3(4-z)=-(z-5)+3

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Solution for 4z+3(4-z)=-(z-5)+3 equation: 



4z+3(4-z)=-(z-5)+3

We move all terms to the left:

4z+3(4-z)-(-(z-5)+3)=0

We add all the numbers together, and all the variables

4z+3(-1z+4)-(-(z-5)+3)=0

We multiply parentheses

4z-3z-(-(z-5)+3)+12=0



We calculate terms in parentheses: -(-(z-5)+3), so:

-(z-5)+3

We get rid of parentheses

-z+5+3

We add all the numbers together, and all the variables

-1z+8

Back to the equation:

-(-1z+8)



We add all the numbers together, and all the variables

z-(-1z+8)+12=0

We get rid of parentheses

z+1z-8+12=0

We add all the numbers together, and all the variables

2z+4=0

We move all terms containing z to the left, all other terms to the right

2z=-4

z=-4/2

z=-2

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