4z+3(z+1)=-22+4(3z-5)

Solution for 4z+3(z+1)=-22+4(3z-5) equation:

Simplifying
4z + 3(z + 1) = -22 + 4(3z + -5)

Reorder the terms:
4z + 3(1 + z) = -22 + 4(3z + -5)
4z + (1 * 3 + z * 3) = -22 + 4(3z + -5)
4z + (3 + 3z) = -22 + 4(3z + -5)

Reorder the terms:
3 + 4z + 3z = -22 + 4(3z + -5)

Combine like terms: 4z + 3z = 7z
3 + 7z = -22 + 4(3z + -5)

Reorder the terms:
3 + 7z = -22 + 4(-5 + 3z)
3 + 7z = -22 + (-5 * 4 + 3z * 4)
3 + 7z = -22 + (-20 + 12z)

Combine like terms: -22 + -20 = -42
3 + 7z = -42 + 12z

Solving
3 + 7z = -42 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
3 + 7z + -12z = -42 + 12z + -12z

Combine like terms: 7z + -12z = -5z
3 + -5z = -42 + 12z + -12z

Combine like terms: 12z + -12z = 0
3 + -5z = -42 + 0
3 + -5z = -42

Add '-3' to each side of the equation.
3 + -3 + -5z = -42 + -3

Combine like terms: 3 + -3 = 0
0 + -5z = -42 + -3
-5z = -42 + -3

Combine like terms: -42 + -3 = -45
-5z = -45

Divide each side by '-5'.
z = 9

Simplifying
z = 9