4z+3+4z+3+5z+2+5z+2=190

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Solution for 4z+3+4z+3+5z+2+5z+2=190 equation: 



4z+3+4z+3+5z+2+5z+2=190

We move all terms to the left:

4z+3+4z+3+5z+2+5z+2-(190)=0

We add all the numbers together, and all the variables

18z-180=0

We move all terms containing z to the left, all other terms to the right

18z=180

z=180/18

z=10

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