4z+3+4z+3+5z+2+5z+2=190

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Solution for 4z+3+4z+3+5z+2+5z+2=190 equation:



4z+3+4z+3+5z+2+5z+2=190
We move all terms to the left:
4z+3+4z+3+5z+2+5z+2-(190)=0
We add all the numbers together, and all the variables
18z-180=0
We move all terms containing z to the left, all other terms to the right
18z=180
z=180/18
z=10

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