4z+33=67

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Solution for 4z+33=67 equation: 



4z+33=67

We move all terms to the left:

4z+33-(67)=0

We add all the numbers together, and all the variables

4z-34=0

We move all terms containing z to the left, all other terms to the right

4z=34

z=34/4

z=8+1/2

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