4z+36=2(4z+4)

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Solution for 4z+36=2(4z+4) equation: 



4z+36=2(4z+4)

We move all terms to the left:

4z+36-(2(4z+4))=0



We calculate terms in parentheses: -(2(4z+4)), so:

2(4z+4)

We multiply parentheses

8z+8

Back to the equation:

-(8z+8)



We get rid of parentheses

4z-8z-8+36=0

We add all the numbers together, and all the variables

-4z+28=0

We move all terms containing z to the left, all other terms to the right

-4z=-28

z=-28/-4

z=+7

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