4z+4+5z+15=40

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Solution for 4z+4+5z+15=40 equation: 



4z+4+5z+15=40

We move all terms to the left:

4z+4+5z+15-(40)=0

We add all the numbers together, and all the variables

9z-21=0

We move all terms containing z to the left, all other terms to the right

9z=21

z=21/9

z=2+1/3

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