4z+4=16-z+3z

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Solution for 4z+4=16-z+3z equation: 



4z+4=16-z+3z

We move all terms to the left:

4z+4-(16-z+3z)=0

We add all the numbers together, and all the variables

4z-(2z+16)+4=0

We get rid of parentheses

4z-2z-16+4=0

We add all the numbers together, and all the variables

2z-12=0

We move all terms containing z to the left, all other terms to the right

2z=12

z=12/2

z=6

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